2.3.1. The power rule
\(\frac{\mathrm{d}}{\mathrm{d}x} x^n = nx^{n-1}\)
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You should be able to differentiate the following types for function
Optionally, also see if you can apply these skills to an economic application or look at the additional resources and advanced quizzes at the bottom of the page,
\(\frac{\mathrm{d}}{\mathrm{d}x} x^n = nx^{n-1}\)
\(\frac{\mathrm{d}}{\mathrm{d}x} e^{ax} = ae^{ax}, \frac{\mathrm{d}}{\mathrm{d}x} \ln{(ax+b)} = \frac{a}{ax+b}\)
\(\left(\frac{u}{v}\right) = \frac{u'v-v'u}{v^2}\)
\(\frac{\mathrm{d}}{\mathrm{d}x} f(g(x)) = f'(g(x)) g'(x)\)
Differentiate more complicated functions by combining the rules above.
Producing output is costly and the relationship between the quantity produced and the cost of production is described by a producer's cost function . On the other hand by producing and selling output the producer realizes revenue and the relationship between the quantity produced and the revenue is described by a producer's revenue function. In deciding how much to produce, a producer should consider if the additional revenue from an extra unit produced exceeds or falls short of the additional cost from producing this extra unit. These rates of change are respectively measured by the marginal cost and the marginal revenue functions. The following application considers how these functions can be obtained by using the rules of differentiation and provides an economic interpretation of the meaning of derivatives.
You can find practice quizzes on each topic in the links above the tutorial videos, or you can take the diagnostic quiz as many times as you like to If you want to test yourself further, then try the advanced quiz linked below.